Base | Representation |
---|---|
bin | 11110100010011111110100… |
… | …100001000000001111001011 |
3 | 122121120002210221001021101122 |
4 | 132202133310201000033023 |
5 | 120101032011244340033 |
6 | 1153354031534105455 |
7 | 40201503115124453 |
oct | 3642376441001713 |
9 | 577502727037348 |
10 | 134312024605643 |
11 | 39883456423305 |
12 | 130926a134b28b |
13 | 59c375347a891 |
14 | 2524a45624d63 |
15 | 107db6d6e3a98 |
hex | 7a27f48403cb |
134312024605643 has 2 divisors, whose sum is σ = 134312024605644. Its totient is φ = 134312024605642.
The previous prime is 134312024605559. The next prime is 134312024605673. The reversal of 134312024605643 is 346506420213431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134312024605643 - 228 = 134311756170187 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134312024605594 and 134312024605603.
It is not a weakly prime, because it can be changed into another prime (134312024605673) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67156012302821 + 67156012302822.
It is an arithmetic number, because the mean of its divisors is an integer number (67156012302822).
Almost surely, 2134312024605643 is an apocalyptic number.
134312024605643 is a deficient number, since it is larger than the sum of its proper divisors (1).
134312024605643 is an equidigital number, since it uses as much as digits as its factorization.
134312024605643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1244160, while the sum is 44.
The spelling of 134312024605643 in words is "one hundred thirty-four trillion, three hundred twelve billion, twenty-four million, six hundred five thousand, six hundred forty-three".
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