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134312124343 = 857199978401
BaseRepresentation
bin111110100010110100…
…0000101111110110111
3110211200102221212011211
41331011220011332313
54200032400434333
6141411354542251
712463244135305
oct1750550057667
9424612855154
10134312124343
1151a63768a61
1222044a37987
13c88637a7b7
14670206b275
1537616deecd
hex1f45a05fb7

134312124343 has 8 divisors (see below), whose sum is σ = 134537832000. Its totient is φ = 134086579200.

The previous prime is 134312124241. The next prime is 134312124371. The reversal of 134312124343 is 343421213431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134312124343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134312124943) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1673943 + ... + 1752343.

It is an arithmetic number, because the mean of its divisors is an integer number (16817229000).

Almost surely, 2134312124343 is an apocalyptic number.

134312124343 is a deficient number, since it is larger than the sum of its proper divisors (225707657).

134312124343 is an equidigital number, since it uses as much as digits as its factorization.

134312124343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81257.

The product of its digits is 20736, while the sum is 31.

Adding to 134312124343 its reverse (343421213431), we get a palindrome (477733337774).

The spelling of 134312124343 in words is "one hundred thirty-four billion, three hundred twelve million, one hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 857 1999 78401 1713143 67189657 156723599 134312124343