1343123011231 has 2 divisors, whose sum is σ = 1343123011232. Its totient is φ = 1343123011230.

The previous prime is 1343123011199. The next prime is 1343123011247. The reversal of 1343123011231 is 1321103213431.

It is a strong prime.

It is an emirp because it is prime and its reverse (1321103213431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1343123011231 - 2⁵ = 1343123011199 is a prime.

It is a super-2 number, since 2×1343123011231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1343123011196 and 1343123011205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343123011831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671561505615 + 671561505616.

It is an arithmetic number, because the mean of its divisors is an integer number (671561505616).

Almost surely, 2^{1343123011231} is an apocalyptic number.

1343123011231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343123011231 is an equidigital number, since it uses as much as digits as its factorization.

1343123011231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1343123011231 its reverse (1321103213431), we get a palindrome (2664226224662).

The spelling of 1343123011231 in words is "one trillion, three hundred forty-three billion, one hundred twenty-three million, eleven thousand, two hundred thirty-one".