Base | Representation |
---|---|
bin | 10011100010111000011… |
… | …100011000001110001111 |
3 | 11202101211122012222220001 |
4 | 103202320130120032033 |
5 | 134001204301241333 |
6 | 2505004525505131 |
7 | 166015604461351 |
oct | 23427034301617 |
9 | 4671748188801 |
10 | 1343124243343 |
11 | 478685690523 |
12 | 1983817121a7 |
13 | 9986b5126ac |
14 | 49016a610d1 |
15 | 24e0ed43b7d |
hex | 138b871838f |
1343124243343 has 4 divisors (see below), whose sum is σ = 1349873611600. Its totient is φ = 1336374875088.
The previous prime is 1343124243311. The next prime is 1343124243371. The reversal of 1343124243343 is 3433424213431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1343124243343 - 25 = 1343124243311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1343124243943) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3374683830 + ... + 3374684227.
It is an arithmetic number, because the mean of its divisors is an integer number (337468402900).
Almost surely, 21343124243343 is an apocalyptic number.
1343124243343 is a deficient number, since it is larger than the sum of its proper divisors (6749368257).
1343124243343 is an equidigital number, since it uses as much as digits as its factorization.
1343124243343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6749368256.
The product of its digits is 248832, while the sum is 37.
Adding to 1343124243343 its reverse (3433424213431), we get a palindrome (4776548456774).
The spelling of 1343124243343 in words is "one trillion, three hundred forty-three billion, one hundred twenty-four million, two hundred forty-three thousand, three hundred forty-three".
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