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1343124556403 = 7191874936629
BaseRepresentation
bin10011100010111000011…
…101100100101001110011
311202101211122210220022212
4103202320131210221303
5134001204341301103
62505004540322335
7166015610234150
oct23427035445163
94671748726285
101343124556403
11478685884753
121983818433ab
139986b5c2036
1449016b03227
1524e0eda67d8
hex138b8764a73

1343124556403 has 4 divisors (see below), whose sum is σ = 1534999493040. Its totient is φ = 1151249619768.

The previous prime is 1343124556391. The next prime is 1343124556429. The reversal of 1343124556403 is 3046554213431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1343124556403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1343124556463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95937468308 + ... + 95937468321.

It is an arithmetic number, because the mean of its divisors is an integer number (383749873260).

Almost surely, 21343124556403 is an apocalyptic number.

1343124556403 is a deficient number, since it is larger than the sum of its proper divisors (191874936637).

1343124556403 is an equidigital number, since it uses as much as digits as its factorization.

1343124556403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191874936636.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 1343124556403 its reverse (3046554213431), we get a palindrome (4389678769834).

The spelling of 1343124556403 in words is "one trillion, three hundred forty-three billion, one hundred twenty-four million, five hundred fifty-six thousand, four hundred three".

Divisors: 1 7 191874936629 1343124556403