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13431403450651 is a prime number
BaseRepresentation
bin1100001101110011111000…
…0010000001000100011011
31202120000210121012111000011
43003130332002001010123
53230030003240410101
644322145045422351
72554246461415204
oct303347602010433
952500717174004
1013431403450651
11430925410139a
12160b119a0a9b7
13765764377b04
14346124ba25ab
151845aced1751
hexc373e08111b

13431403450651 has 2 divisors, whose sum is σ = 13431403450652. Its totient is φ = 13431403450650.

The previous prime is 13431403450609. The next prime is 13431403450693. The reversal of 13431403450651 is 15605430413431.

It is a balanced prime because it is at equal distance from previous prime (13431403450609) and next prime (13431403450693).

It is a cyclic number.

It is not a de Polignac number, because 13431403450651 - 27 = 13431403450523 is a prime.

It is a super-3 number, since 3×134314034506513 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13431403456651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715701725325 + 6715701725326.

It is an arithmetic number, because the mean of its divisors is an integer number (6715701725326).

Almost surely, 213431403450651 is an apocalyptic number.

13431403450651 is a deficient number, since it is larger than the sum of its proper divisors (1).

13431403450651 is an equidigital number, since it uses as much as digits as its factorization.

13431403450651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 13431403450651 in words is "thirteen trillion, four hundred thirty-one billion, four hundred three million, four hundred fifty thousand, six hundred fifty-one".