Base | Representation |
---|---|
bin | 11001000001001001… |
… | …11001001010010011 |
3 | 1021200001122001112011 |
4 | 30200210321022103 |
5 | 210001422202430 |
6 | 10100442243351 |
7 | 653562251125 |
oct | 144044711223 |
9 | 37601561464 |
10 | 13431444115 |
11 | 5772777841 |
12 | 272a1b6557 |
13 | 13608a268b |
14 | 915b97215 |
15 | 53927722a |
hex | 320939293 |
13431444115 has 4 divisors (see below), whose sum is σ = 16117732944. Its totient is φ = 10745155288.
The previous prime is 13431444101. The next prime is 13431444119. The reversal of 13431444115 is 51144413431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13431444115 - 215 = 13431411347 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13431444119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1343144407 + ... + 1343144416.
It is an arithmetic number, because the mean of its divisors is an integer number (4029433236).
Almost surely, 213431444115 is an apocalyptic number.
13431444115 is a deficient number, since it is larger than the sum of its proper divisors (2686288829).
13431444115 is an equidigital number, since it uses as much as digits as its factorization.
13431444115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2686288828.
The product of its digits is 11520, while the sum is 31.
Adding to 13431444115 its reverse (51144413431), we get a palindrome (64575857546).
The spelling of 13431444115 in words is "thirteen billion, four hundred thirty-one million, four hundred forty-four thousand, one hundred fifteen".
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