Base | Representation |
---|---|
bin | 10011100010111001101… |
… | …101011110100100111011 |
3 | 11202101220010020002201001 |
4 | 103202321231132210323 |
5 | 134001230222044120 |
6 | 2505011005305431 |
7 | 166016253255100 |
oct | 23427155364473 |
9 | 4671803202631 |
10 | 1343145503035 |
11 | 478696691216 |
12 | 198388865277 |
13 | 99872a472ab |
14 | 490197d6aa7 |
15 | 24e11b42e0a |
hex | 138b9b5e93b |
1343145503035 has 24 divisors (see below), whose sum is σ = 1881593892576. Its totient is φ = 917736382080.
The previous prime is 1343145502999. The next prime is 1343145503101. The reversal of 1343145503035 is 5303055413431.
It is not a de Polignac number, because 1343145503035 - 221 = 1343143405883 is a prime.
It is a super-2 number, since 2×13431455030352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1343145502985 and 1343145503003.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9686007 + ... + 9823696.
It is an arithmetic number, because the mean of its divisors is an integer number (78399745524).
Almost surely, 21343145503035 is an apocalyptic number.
1343145503035 is a deficient number, since it is larger than the sum of its proper divisors (538448389541).
1343145503035 is a wasteful number, since it uses less digits than its factorization.
1343145503035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19510003 (or 19509996 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 37.
The spelling of 1343145503035 in words is "one trillion, three hundred forty-three billion, one hundred forty-five million, five hundred three thousand, thirty-five".
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