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1343145503035 = 57228119509703
BaseRepresentation
bin10011100010111001101…
…101011110100100111011
311202101220010020002201001
4103202321231132210323
5134001230222044120
62505011005305431
7166016253255100
oct23427155364473
94671803202631
101343145503035
11478696691216
12198388865277
1399872a472ab
14490197d6aa7
1524e11b42e0a
hex138b9b5e93b

1343145503035 has 24 divisors (see below), whose sum is σ = 1881593892576. Its totient is φ = 917736382080.

The previous prime is 1343145502999. The next prime is 1343145503101. The reversal of 1343145503035 is 5303055413431.

It is not a de Polignac number, because 1343145503035 - 221 = 1343143405883 is a prime.

It is a super-2 number, since 2×13431455030352 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1343145502985 and 1343145503003.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9686007 + ... + 9823696.

It is an arithmetic number, because the mean of its divisors is an integer number (78399745524).

Almost surely, 21343145503035 is an apocalyptic number.

1343145503035 is a deficient number, since it is larger than the sum of its proper divisors (538448389541).

1343145503035 is a wasteful number, since it uses less digits than its factorization.

1343145503035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19510003 (or 19509996 counting only the distinct ones).

The product of its (nonzero) digits is 162000, while the sum is 37.

The spelling of 1343145503035 in words is "one trillion, three hundred forty-three billion, one hundred forty-five million, five hundred three thousand, thirty-five".

Divisors: 1 5 7 35 49 245 281 1405 1967 9835 13769 68845 19509703 97548515 136567921 682839605 955975447 4779877235 5482226543 27411132715 38375585801 191877929005 268629100607 1343145503035