Base | Representation |
---|---|
bin | 1100001101110100011011… |
… | …0001111110110011100111 |
3 | 1202120001011211102020220122 |
4 | 3003131012301332303213 |
5 | 3230030303330221043 |
6 | 44322211411552155 |
7 | 2554253223212324 |
oct | 303350661766347 |
9 | 52501154366818 |
10 | 13431550242023 |
11 | 4309319a51981 |
12 | 160b15abbb65b |
13 | 7657888c2404 |
14 | 34613a493b4b |
15 | 1845bad2a368 |
hex | c3746c7ece7 |
13431550242023 has 2 divisors, whose sum is σ = 13431550242024. Its totient is φ = 13431550242022.
The previous prime is 13431550241999. The next prime is 13431550242037. The reversal of 13431550242023 is 32024205513431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13431550242023 - 216 = 13431550176487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13431550242923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715775121011 + 6715775121012.
It is an arithmetic number, because the mean of its divisors is an integer number (6715775121012).
Almost surely, 213431550242023 is an apocalyptic number.
13431550242023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13431550242023 is an equidigital number, since it uses as much as digits as its factorization.
13431550242023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 13431550242023 its reverse (32024205513431), we get a palindrome (45455755755454).
The spelling of 13431550242023 in words is "thirteen trillion, four hundred thirty-one billion, five hundred fifty million, two hundred forty-two thousand, twenty-three".
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