Base | Representation |
---|---|
bin | 111110100010111110… |
… | …1010111001111011111 |
3 | 110211200211110010121222 |
4 | 1331011331113033133 |
5 | 4200040312400223 |
6 | 141412114243555 |
7 | 12463342420121 |
oct | 1750575271737 |
9 | 424624403558 |
10 | 134317700063 |
11 | 51a66927098 |
12 | 220468865bb |
13 | c887580641 |
14 | 6702abd211 |
15 | 3761e420c8 |
hex | 1f45f573df |
134317700063 has 2 divisors, whose sum is σ = 134317700064. Its totient is φ = 134317700062.
The previous prime is 134317700059. The next prime is 134317700081. The reversal of 134317700063 is 360007713431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134317700063 - 22 = 134317700059 is a prime.
It is a super-4 number, since 4×1343177000634 (a number of 46 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134317699996 and 134317700032.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134317700053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67158850031 + 67158850032.
It is an arithmetic number, because the mean of its divisors is an integer number (67158850032).
Almost surely, 2134317700063 is an apocalyptic number.
134317700063 is a deficient number, since it is larger than the sum of its proper divisors (1).
134317700063 is an equidigital number, since it uses as much as digits as its factorization.
134317700063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31752, while the sum is 35.
The spelling of 134317700063 in words is "one hundred thirty-four billion, three hundred seventeen million, seven hundred thousand, sixty-three".
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