Base | Representation |
---|---|
bin | 10011100010111101000… |
… | …101011010111000100011 |
3 | 11202102001001202002020202 |
4 | 103202331011122320203 |
5 | 134001334220023021 |
6 | 2505020350455415 |
7 | 166020541363655 |
oct | 23427505327043 |
9 | 4672031662222 |
10 | 1343202111011 |
11 | 478715635672 |
12 | 1983a380456b |
13 | 998816a7337 |
14 | 490231306d5 |
15 | 24e16ac5a0b |
hex | 138bd15ae23 |
1343202111011 has 4 divisors (see below), whose sum is σ = 1422213999912. Its totient is φ = 1264190222112.
The previous prime is 1343202111001. The next prime is 1343202111037. The reversal of 1343202111011 is 1101112023431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1343202111011 is a prime.
It is a super-2 number, since 2×13432021110112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1343202111001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39505944425 + ... + 39505944458.
It is an arithmetic number, because the mean of its divisors is an integer number (355553499978).
Almost surely, 21343202111011 is an apocalyptic number.
1343202111011 is a deficient number, since it is larger than the sum of its proper divisors (79011888901).
1343202111011 is an equidigital number, since it uses as much as digits as its factorization.
1343202111011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79011888900.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1343202111011 its reverse (1101112023431), we get a palindrome (2444314134442).
The spelling of 1343202111011 in words is "one trillion, three hundred forty-three billion, two hundred two million, one hundred eleven thousand, eleven".
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