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1343202111011 = 1779011888883
BaseRepresentation
bin10011100010111101000…
…101011010111000100011
311202102001001202002020202
4103202331011122320203
5134001334220023021
62505020350455415
7166020541363655
oct23427505327043
94672031662222
101343202111011
11478715635672
121983a380456b
13998816a7337
14490231306d5
1524e16ac5a0b
hex138bd15ae23

1343202111011 has 4 divisors (see below), whose sum is σ = 1422213999912. Its totient is φ = 1264190222112.

The previous prime is 1343202111001. The next prime is 1343202111037. The reversal of 1343202111011 is 1101112023431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1343202111011 is a prime.

It is a super-2 number, since 2×13432021110112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1343202111001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39505944425 + ... + 39505944458.

It is an arithmetic number, because the mean of its divisors is an integer number (355553499978).

Almost surely, 21343202111011 is an apocalyptic number.

1343202111011 is a deficient number, since it is larger than the sum of its proper divisors (79011888901).

1343202111011 is an equidigital number, since it uses as much as digits as its factorization.

1343202111011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79011888900.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1343202111011 its reverse (1101112023431), we get a palindrome (2444314134442).

The spelling of 1343202111011 in words is "one trillion, three hundred forty-three billion, two hundred two million, one hundred eleven thousand, eleven".

Divisors: 1 17 79011888883 1343202111011