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134320554414421 is a prime number
BaseRepresentation
bin11110100010100111110000…
…111011101001000101010101
3122121120220211101101110022021
4132202213300323221011111
5120101201443412230141
61153402002201333141
740202224361242564
oct3642476073510525
9577526741343267
10134320554414421
1139887033267951
1213094281a971b1
1359c44b26b19cb
142525214403bdb
15107debc4946d1
hex7a29f0ee9155

134320554414421 has 2 divisors, whose sum is σ = 134320554414422. Its totient is φ = 134320554414420.

The previous prime is 134320554414377. The next prime is 134320554414427. The reversal of 134320554414421 is 124414455023431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114977367562500 + 19343186851921 = 10722750^2 + 4398089^2 .

It is a cyclic number.

It is not a de Polignac number, because 134320554414421 - 29 = 134320554413909 is a prime.

It is a super-2 number, since 2×1343205544144212 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134320554414427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67160277207210 + 67160277207211.

It is an arithmetic number, because the mean of its divisors is an integer number (67160277207211).

Almost surely, 2134320554414421 is an apocalyptic number.

It is an amenable number.

134320554414421 is a deficient number, since it is larger than the sum of its proper divisors (1).

134320554414421 is an equidigital number, since it uses as much as digits as its factorization.

134320554414421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 921600, while the sum is 43.

The spelling of 134320554414421 in words is "one hundred thirty-four trillion, three hundred twenty billion, five hundred fifty-four million, four hundred fourteen thousand, four hundred twenty-one".