Base | Representation |
---|---|
bin | 10011100010111101100… |
… | …111010110000101000111 |
3 | 11202102001200110220110021 |
4 | 103202331213112011013 |
5 | 134001344004113411 |
6 | 2505021305240011 |
7 | 166021010103505 |
oct | 23427547260507 |
9 | 4672050426407 |
10 | 1343211004231 |
11 | 47871a65a238 |
12 | 1983a6793007 |
13 | 9988349c1b5 |
14 | 490243a7675 |
15 | 24e17780a71 |
hex | 138bd9d6147 |
1343211004231 has 2 divisors, whose sum is σ = 1343211004232. Its totient is φ = 1343211004230.
The previous prime is 1343211004211. The next prime is 1343211004243. The reversal of 1343211004231 is 1324001123431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1343211004231 - 225 = 1343177449799 is a prime.
It is a super-2 number, since 2×13432110042312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1343211004196 and 1343211004205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343211004211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671605502115 + 671605502116.
It is an arithmetic number, because the mean of its divisors is an integer number (671605502116).
Almost surely, 21343211004231 is an apocalyptic number.
1343211004231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343211004231 is an equidigital number, since it uses as much as digits as its factorization.
1343211004231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1343211004231 its reverse (1324001123431), we get a palindrome (2667212127662).
The spelling of 1343211004231 in words is "one trillion, three hundred forty-three billion, two hundred eleven million, four thousand, two hundred thirty-one".
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