Base | Representation |
---|---|
bin | 1100001101110110110110… |
… | …0100011011100101011111 |
3 | 1202120002212011221020211111 |
4 | 3003131231210123211133 |
5 | 3230033121424020221 |
6 | 44322400140002451 |
7 | 2554305314450611 |
oct | 303355544334537 |
9 | 52502764836744 |
10 | 13432201001311 |
11 | 4309623319a74 |
12 | 160b300b30427 |
13 | 765860680b91 |
14 | 34619ca90db1 |
15 | 184608022be1 |
hex | c376d91b95f |
13432201001311 has 2 divisors, whose sum is σ = 13432201001312. Its totient is φ = 13432201001310.
The previous prime is 13432201001293. The next prime is 13432201001327. The reversal of 13432201001311 is 11310010223431.
It is a strong prime.
It is an emirp because it is prime and its reverse (11310010223431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13432201001311 - 27 = 13432201001183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13432201001381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6716100500655 + 6716100500656.
It is an arithmetic number, because the mean of its divisors is an integer number (6716100500656).
Almost surely, 213432201001311 is an apocalyptic number.
13432201001311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13432201001311 is an equidigital number, since it uses as much as digits as its factorization.
13432201001311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 13432201001311 its reverse (11310010223431), we get a palindrome (24742211224742).
The spelling of 13432201001311 in words is "thirteen trillion, four hundred thirty-two billion, two hundred one million, one thousand, three hundred eleven".
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