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1343224512103 = 11171202528659
BaseRepresentation
bin10011100010111110011…
…010110111111001100111
311202102002121220011202211
4103202332122313321213
5134001410433341403
62505022510544251
7166021232653165
oct23427632677147
94672077804684
101343224512103
11478727245971
121983ab208087
139988621b616
14490260c2235
1524e18a4d06d
hex138be6b7e67

1343224512103 has 4 divisors (see below), whose sum is σ = 1344427041880. Its totient is φ = 1342021982328.

The previous prime is 1343224512083. The next prime is 1343224512121. The reversal of 1343224512103 is 3012154223431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1343224512103 - 225 = 1343190957671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343224522103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601263213 + ... + 601265446.

It is an arithmetic number, because the mean of its divisors is an integer number (336106760470).

Almost surely, 21343224512103 is an apocalyptic number.

1343224512103 is a deficient number, since it is larger than the sum of its proper divisors (1202529777).

1343224512103 is a wasteful number, since it uses less digits than its factorization.

1343224512103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1202529776.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1343224512103 its reverse (3012154223431), we get a palindrome (4355378735534).

The spelling of 1343224512103 in words is "one trillion, three hundred forty-three billion, two hundred twenty-four million, five hundred twelve thousand, one hundred three".

Divisors: 1 1117 1202528659 1343224512103