1343247667603 has 4 divisors (see below), whose sum is σ = 1357095581800. Its totient is φ = 1329399753408.

The previous prime is 1343247667571. The next prime is 1343247667609. The reversal of 1343247667603 is 3067667423431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1343247667603 - 2⁵ = 1343247667571 is a prime.

It is a super-3 number, since 3×1343247667603³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1343247667609) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6923956953 + ... + 6923957146.

It is an arithmetic number, because the mean of its divisors is an integer number (339273895450).

Almost surely, 2^{1343247667603} is an apocalyptic number.

1343247667603 is a deficient number, since it is larger than the sum of its proper divisors (13847914197).

1343247667603 is an equidigital number, since it uses as much as digits as its factorization.

1343247667603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13847914196.

The product of its (nonzero) digits is 9144576, while the sum is 52.

The spelling of 1343247667603 in words is "one trillion, three hundred forty-three billion, two hundred forty-seven million, six hundred sixty-seven thousand, six hundred three".