13433105401 has 4 divisors (see below), whose sum is σ = 13434285904. Its totient is φ = 13431924900.

The previous prime is 13433105383. The next prime is 13433105453. The reversal of 13433105401 is 10450133431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13433105401 - 2¹¹ = 13433103353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13433105461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 573015 + ... + 595996.

It is an arithmetic number, because the mean of its divisors is an integer number (3358571476).

Almost surely, 2^13433105401 is an apocalyptic number.

It is an amenable number.

13433105401 is a deficient number, since it is larger than the sum of its proper divisors (1180503).

13433105401 is a wasteful number, since it uses less digits than its factorization.

13433105401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1180502.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 13433105401 its reverse (10450133431), we get a palindrome (23883238832).

The spelling of 13433105401 in words is "thirteen billion, four hundred thirty-three million, one hundred five thousand, four hundred one".