Base | Representation |
---|---|
bin | 111110100011011000… |
… | …0100100000111100011 |
3 | 110211201202201001021012 |
4 | 1331012300210013203 |
5 | 4200102231402042 |
6 | 141413314051135 |
7 | 12463564461425 |
oct | 1750660440743 |
9 | 424652631235 |
10 | 134331122147 |
11 | 51a73464322 |
12 | 2204b279aab |
13 | c88a29c9c1 |
14 | 67047b4815 |
15 | 37631e3e82 |
hex | 1f46c241e3 |
134331122147 has 2 divisors, whose sum is σ = 134331122148. Its totient is φ = 134331122146.
The previous prime is 134331122143. The next prime is 134331122183. The reversal of 134331122147 is 741221133431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134331122147 - 22 = 134331122143 is a prime.
It is not a weakly prime, because it can be changed into another prime (134331122141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165561073 + 67165561074.
It is an arithmetic number, because the mean of its divisors is an integer number (67165561074).
Almost surely, 2134331122147 is an apocalyptic number.
134331122147 is a deficient number, since it is larger than the sum of its proper divisors (1).
134331122147 is an equidigital number, since it uses as much as digits as its factorization.
134331122147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12096, while the sum is 32.
Adding to 134331122147 its reverse (741221133431), we get a palindrome (875552255578).
The spelling of 134331122147 in words is "one hundred thirty-four billion, three hundred thirty-one million, one hundred twenty-two thousand, one hundred forty-seven".
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