Search a number
-
+
134331122143 is a prime number
BaseRepresentation
bin111110100011011000…
…0100100000111011111
3110211201202201001021001
41331012300210013133
54200102231402033
6141413314051131
712463564461421
oct1750660440737
9424652631231
10134331122143
1151a73464319
122204b279aa7
13c88a29c9ba
1467047b4811
1537631e3e7d
hex1f46c241df

134331122143 has 2 divisors, whose sum is σ = 134331122144. Its totient is φ = 134331122142.

The previous prime is 134331122141. The next prime is 134331122147. The reversal of 134331122143 is 341221133431.

It is a weak prime.

It is an emirp because it is prime and its reverse (341221133431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134331122143 - 21 = 134331122141 is a prime.

Together with 134331122141, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134331122141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165561071 + 67165561072.

It is an arithmetic number, because the mean of its divisors is an integer number (67165561072).

Almost surely, 2134331122143 is an apocalyptic number.

134331122143 is a deficient number, since it is larger than the sum of its proper divisors (1).

134331122143 is an equidigital number, since it uses as much as digits as its factorization.

134331122143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 28.

Adding to 134331122143 its reverse (341221133431), we get a palindrome (475552255574).

The spelling of 134331122143 in words is "one hundred thirty-four billion, three hundred thirty-one million, one hundred twenty-two thousand, one hundred forty-three".