1343311410439 has 2 divisors, whose sum is σ = 1343311410440. Its totient is φ = 1343311410438.

The previous prime is 1343311410379. The next prime is 1343311410503. The reversal of 1343311410439 is 9340141133431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1343311410439 - 2¹³ = 1343311402247 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1343311410398 and 1343311410407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343311411439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671655705219 + 671655705220.

It is an arithmetic number, because the mean of its divisors is an integer number (671655705220).

Almost surely, 2^{1343311410439} is an apocalyptic number.

1343311410439 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343311410439 is an equidigital number, since it uses as much as digits as its factorization.

1343311410439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 37.

The spelling of 1343311410439 in words is "one trillion, three hundred forty-three billion, three hundred eleven million, four hundred ten thousand, four hundred thirty-nine".