Base | Representation |
---|---|
bin | 10011100011000011110… |
… | …001001011000111001111 |
3 | 11202102022212202000212011 |
4 | 103203003301023013033 |
5 | 134002101421302142 |
6 | 2505035434122051 |
7 | 166023402451306 |
oct | 23430361130717 |
9 | 4672285660764 |
10 | 1343314244047 |
11 | 4787729638a6 |
12 | 198415280327 |
13 | 9989b9a8549 |
14 | 49033d9d43d |
15 | 24e21875417 |
hex | 138c3c4b1cf |
1343314244047 has 2 divisors, whose sum is σ = 1343314244048. Its totient is φ = 1343314244046.
The previous prime is 1343314244017. The next prime is 1343314244057. The reversal of 1343314244047 is 7404424133431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1343314244047 - 231 = 1341166760399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343314244017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671657122023 + 671657122024.
It is an arithmetic number, because the mean of its divisors is an integer number (671657122024).
Almost surely, 21343314244047 is an apocalyptic number.
1343314244047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343314244047 is an equidigital number, since it uses as much as digits as its factorization.
1343314244047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 40.
Adding to 1343314244047 its reverse (7404424133431), we get a palindrome (8747738377478).
The spelling of 1343314244047 in words is "one trillion, three hundred forty-three billion, three hundred fourteen million, two hundred forty-four thousand, forty-seven".
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