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1343315514137 is a prime number
BaseRepresentation
bin10011100011000011110…
…110000001001100011001
311202102022222010120002112
4103203003312001030121
5134002102232423022
62505035521242105
7166023416321222
oct23430366011431
94672288116075
101343315514137
11478773651063
12198415793335
139989c03168c
1449034210249
1524e21a268e2
hex138c3d81319

1343315514137 has 2 divisors, whose sum is σ = 1343315514138. Its totient is φ = 1343315514136.

The previous prime is 1343315514103. The next prime is 1343315514181. The reversal of 1343315514137 is 7314155133431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1220364299401 + 122951214736 = 1104701^2 + 350644^2 .

It is an emirp because it is prime and its reverse (7314155133431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1343315514137 - 226 = 1343248405273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1343315514094 and 1343315514103.

It is not a weakly prime, because it can be changed into another prime (1343315519137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671657757068 + 671657757069.

It is an arithmetic number, because the mean of its divisors is an integer number (671657757069).

Almost surely, 21343315514137 is an apocalyptic number.

It is an amenable number.

1343315514137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343315514137 is an equidigital number, since it uses as much as digits as its factorization.

1343315514137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 226800, while the sum is 41.

The spelling of 1343315514137 in words is "one trillion, three hundred forty-three billion, three hundred fifteen million, five hundred fourteen thousand, one hundred thirty-seven".