Base | Representation |
---|---|
bin | 10011100011000011110… |
… | …110000001001101000101 |
3 | 11202102022222010120011011 |
4 | 103203003312001031011 |
5 | 134002102232423211 |
6 | 2505035521242221 |
7 | 166023416321314 |
oct | 23430366011505 |
9 | 4672288116134 |
10 | 1343315514181 |
11 | 4787736510a3 |
12 | 198415793371 |
13 | 9989c0316c4 |
14 | 4903421027b |
15 | 24e21a26921 |
hex | 138c3d81345 |
1343315514181 has 2 divisors, whose sum is σ = 1343315514182. Its totient is φ = 1343315514180.
The previous prime is 1343315514137. The next prime is 1343315514193. The reversal of 1343315514181 is 1814155133431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 702187017156 + 641128497025 = 837966^2 + 800705^2 .
It is an emirp because it is prime and its reverse (1814155133431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1343315514181 is a prime.
It is a super-2 number, since 2×13433155141812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343315514881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671657757090 + 671657757091.
It is an arithmetic number, because the mean of its divisors is an integer number (671657757091).
Almost surely, 21343315514181 is an apocalyptic number.
It is an amenable number.
1343315514181 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343315514181 is an equidigital number, since it uses as much as digits as its factorization.
1343315514181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 86400, while the sum is 40.
The spelling of 1343315514181 in words is "one trillion, three hundred forty-three billion, three hundred fifteen million, five hundred fourteen thousand, one hundred eighty-one".
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