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1343315515021 is a prime number
BaseRepresentation
bin10011100011000011110…
…110000001011010001101
311202102022222010121022021
4103203003312001122031
5134002102232440041
62505035521250141
7166023416323624
oct23430366013215
94672288117267
101343315515021
11478773651797
12198415793951
139989c031bbc
14490342106bb
1524e21a26cd1
hex138c3d8168d

1343315515021 has 2 divisors, whose sum is σ = 1343315515022. Its totient is φ = 1343315515020.

The previous prime is 1343315515013. The next prime is 1343315515067. The reversal of 1343315515021 is 1205155133431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1074384075625 + 268931439396 = 1036525^2 + 518586^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343315515021 - 23 = 1343315515013 is a prime.

It is a super-2 number, since 2×13433155150212 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343315515921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671657757510 + 671657757511.

It is an arithmetic number, because the mean of its divisors is an integer number (671657757511).

Almost surely, 21343315515021 is an apocalyptic number.

It is an amenable number.

1343315515021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343315515021 is an equidigital number, since it uses as much as digits as its factorization.

1343315515021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 34.

The spelling of 1343315515021 in words is "one trillion, three hundred forty-three billion, three hundred fifteen million, five hundred fifteen thousand, twenty-one".