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1343315515103 is a prime number
BaseRepresentation
bin10011100011000011110…
…110000001011011011111
311202102022222010121102022
4103203003312001123133
5134002102232440403
62505035521250355
7166023416324102
oct23430366013337
94672288117368
101343315515103
11478773651861
121984157939bb
139989c031c53
1449034210739
1524e21a26d38
hex138c3d816df

1343315515103 has 2 divisors, whose sum is σ = 1343315515104. Its totient is φ = 1343315515102.

The previous prime is 1343315515067. The next prime is 1343315515109. The reversal of 1343315515103 is 3015155133431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1343315515103 - 238 = 1068437608159 is a prime.

It is a super-2 number, since 2×13433155151032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343315515109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671657757551 + 671657757552.

It is an arithmetic number, because the mean of its divisors is an integer number (671657757552).

Almost surely, 21343315515103 is an apocalyptic number.

1343315515103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343315515103 is an equidigital number, since it uses as much as digits as its factorization.

1343315515103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40500, while the sum is 35.

The spelling of 1343315515103 in words is "one trillion, three hundred forty-three billion, three hundred fifteen million, five hundred fifteen thousand, one hundred three".