Base | Representation |
---|---|
bin | 10011100011000011110… |
… | …110000001011011011111 |
3 | 11202102022222010121102022 |
4 | 103203003312001123133 |
5 | 134002102232440403 |
6 | 2505035521250355 |
7 | 166023416324102 |
oct | 23430366013337 |
9 | 4672288117368 |
10 | 1343315515103 |
11 | 478773651861 |
12 | 1984157939bb |
13 | 9989c031c53 |
14 | 49034210739 |
15 | 24e21a26d38 |
hex | 138c3d816df |
1343315515103 has 2 divisors, whose sum is σ = 1343315515104. Its totient is φ = 1343315515102.
The previous prime is 1343315515067. The next prime is 1343315515109. The reversal of 1343315515103 is 3015155133431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1343315515103 - 238 = 1068437608159 is a prime.
It is a super-2 number, since 2×13433155151032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343315515109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671657757551 + 671657757552.
It is an arithmetic number, because the mean of its divisors is an integer number (671657757552).
Almost surely, 21343315515103 is an apocalyptic number.
1343315515103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343315515103 is an equidigital number, since it uses as much as digits as its factorization.
1343315515103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 35.
The spelling of 1343315515103 in words is "one trillion, three hundred forty-three billion, three hundred fifteen million, five hundred fifteen thousand, one hundred three".
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