Base | Representation |
---|---|
bin | 10011100011000100001… |
… | …101011011001110111111 |
3 | 11202102100101200022001211 |
4 | 103203010031123032333 |
5 | 134002110320300421 |
6 | 2505040300545251 |
7 | 166023522425320 |
oct | 23430415331677 |
9 | 4672311608054 |
10 | 1343321650111 |
11 | 478777062111 |
12 | 198417852227 |
13 | 998a039c52c |
14 | 49034d6a447 |
15 | 24e223399e1 |
hex | 138c435b3bf |
1343321650111 has 16 divisors (see below), whose sum is σ = 1562468175360. Its totient is φ = 1131103078560.
The previous prime is 1343321650067. The next prime is 1343321650117. The reversal of 1343321650111 is 1110561233431.
It is not a de Polignac number, because 1343321650111 - 211 = 1343321648063 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1343321650117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4741141 + ... + 5016478.
It is an arithmetic number, because the mean of its divisors is an integer number (97654260960).
Almost surely, 21343321650111 is an apocalyptic number.
1343321650111 is a deficient number, since it is larger than the sum of its proper divisors (219146525249).
1343321650111 is an equidigital number, since it uses as much as digits as its factorization.
1343321650111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9757974.
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 1343321650111 its reverse (1110561233431), we get a palindrome (2453882883542).
The spelling of 1343321650111 in words is "one trillion, three hundred forty-three billion, three hundred twenty-one million, six hundred fifty thousand, one hundred eleven".
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