Base | Representation |
---|---|
bin | 11110100010110011011001… |
… | …111110100011000011110001 |
3 | 122121122010002111221110110101 |
4 | 132202303121332203003301 |
5 | 120101403043333431342 |
6 | 1153411430403232401 |
7 | 40203146211550342 |
oct | 3642633176430361 |
9 | 577563074843411 |
10 | 134333054202097 |
11 | 39891368050393 |
12 | 13096790078701 |
13 | 59c5725255a8a |
14 | 2525a7c5600c9 |
15 | 107e49ea3a3b7 |
hex | 7a2cd9fa30f1 |
134333054202097 has 2 divisors, whose sum is σ = 134333054202098. Its totient is φ = 134333054202096.
The previous prime is 134333054202077. The next prime is 134333054202121. The reversal of 134333054202097 is 790202450333431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98385846833296 + 35947207368801 = 9918964^2 + 5995599^2 .
It is a cyclic number.
It is not a de Polignac number, because 134333054202097 - 235 = 134298694463729 is a prime.
It is not a weakly prime, because it can be changed into another prime (134333054202077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166527101048 + 67166527101049.
It is an arithmetic number, because the mean of its divisors is an integer number (67166527101049).
Almost surely, 2134333054202097 is an apocalyptic number.
It is an amenable number.
134333054202097 is a deficient number, since it is larger than the sum of its proper divisors (1).
134333054202097 is an equidigital number, since it uses as much as digits as its factorization.
134333054202097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1632960, while the sum is 46.
The spelling of 134333054202097 in words is "one hundred thirty-four trillion, three hundred thirty-three billion, fifty-four million, two hundred two thousand, ninety-seven".
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