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134333054202077 is a prime number
BaseRepresentation
bin11110100010110011011001…
…111110100011000011011101
3122121122010002111221110102122
4132202303121332203003131
5120101403043333431302
61153411430403232325
740203146211550313
oct3642633176430335
9577563074843378
10134333054202077
1139891368050375
12130967900786a5
1359c5725255a73
142525a7c5600b3
15107e49ea3a3a2
hex7a2cd9fa30dd

134333054202077 has 2 divisors, whose sum is σ = 134333054202078. Its totient is φ = 134333054202076.

The previous prime is 134333054202071. The next prime is 134333054202097. The reversal of 134333054202077 is 770202450333431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122749248759076 + 11583805443001 = 11079226^2 + 3403499^2 .

It is an emirp because it is prime and its reverse (770202450333431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134333054202077 - 222 = 134333050007773 is a prime.

It is a super-2 number, since 2×1343330542020772 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134333054202071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166527101038 + 67166527101039.

It is an arithmetic number, because the mean of its divisors is an integer number (67166527101039).

Almost surely, 2134333054202077 is an apocalyptic number.

It is an amenable number.

134333054202077 is a deficient number, since it is larger than the sum of its proper divisors (1).

134333054202077 is an equidigital number, since it uses as much as digits as its factorization.

134333054202077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1270080, while the sum is 44.

The spelling of 134333054202077 in words is "one hundred thirty-four trillion, three hundred thirty-three billion, fifty-four million, two hundred two thousand, seventy-seven".