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134333234219 is a prime number
BaseRepresentation
bin111110100011011100…
…0100111110000101011
3110211201220200100111002
41331012320213300223
54200103301443334
6141413431225215
712463621436162
oct1750670476053
9424656610432
10134333234219
1151a74677138
122204bb1820b
13c88a85c152
146704ba43d9
1537634aeb7e
hex1f46e27c2b

134333234219 has 2 divisors, whose sum is σ = 134333234220. Its totient is φ = 134333234218.

The previous prime is 134333234197. The next prime is 134333234221. The reversal of 134333234219 is 912432333431.

It is a strong prime.

It is an emirp because it is prime and its reverse (912432333431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134333234219 - 212 = 134333230123 is a prime.

It is a super-2 number, since 2×1343332342192 (a number of 23 digits) contains 22 as substring.

Together with 134333234221, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (134333234249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166617109 + 67166617110.

It is an arithmetic number, because the mean of its divisors is an integer number (67166617110).

Almost surely, 2134333234219 is an apocalyptic number.

134333234219 is a deficient number, since it is larger than the sum of its proper divisors (1).

134333234219 is an equidigital number, since it uses as much as digits as its factorization.

134333234219 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 139968, while the sum is 38.

The spelling of 134333234219 in words is "one hundred thirty-four billion, three hundred thirty-three million, two hundred thirty-four thousand, two hundred nineteen".