13433341044141 has 16 divisors (see below), whose sum is σ = 20766517557120. Its totient is φ = 8566188491520.

The previous prime is 13433341044107. The next prime is 13433341044197. The reversal of 13433341044141 is 14144014333431.

13433341044141 is a `hidden beast` number, since 1 + 3 + 433 + 3 + 41 + 0 + 44 + 141 = 666.

It is not a de Polignac number, because 13433341044141 - 2¹⁸ = 13433340781997 is a prime.

It is a super-2 number, since 2×13433341044141² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13433341044096 and 13433341044105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13433341044941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10815893940 + ... + 10815895181.

It is an arithmetic number, because the mean of its divisors is an integer number (1297907347320).

Almost surely, 2^{13433341044141} is an apocalyptic number.

It is an amenable number.

13433341044141 is a deficient number, since it is larger than the sum of its proper divisors (7333176512979).

13433341044141 is a wasteful number, since it uses less digits than its factorization.

13433341044141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21631789153 (or 21631789147 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 36.

Adding to 13433341044141 its reverse (14144014333431), we get a palindrome (27577355377572).

The spelling of 13433341044141 in words is "thirteen trillion, four hundred thirty-three billion, three hundred forty-one million, forty-four thousand, one hundred forty-one".