Base | Representation |
---|---|
bin | 101000000010001… |
… | …1110011011011101 |
3 | 10110121202021102222 |
4 | 1100010132123131 |
5 | 10222344203433 |
6 | 341144355125 |
7 | 45201201512 |
oct | 12004363335 |
9 | 3417667388 |
10 | 1343350493 |
11 | 62a317121 |
12 | 315a75aa5 |
13 | 185405864 |
14 | ca5a7309 |
15 | 7ce04b98 |
hex | 5011e6dd |
1343350493 has 2 divisors, whose sum is σ = 1343350494. Its totient is φ = 1343350492.
The previous prime is 1343350457. The next prime is 1343350513. The reversal of 1343350493 is 3940533431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1276061284 + 67289209 = 35722^2 + 8203^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1343350493 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343350403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671675246 + 671675247.
It is an arithmetic number, because the mean of its divisors is an integer number (671675247).
Almost surely, 21343350493 is an apocalyptic number.
It is an amenable number.
1343350493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343350493 is an equidigital number, since it uses as much as digits as its factorization.
1343350493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58320, while the sum is 35.
The square root of 1343350493 is about 36651.7461112019. The cubic root of 1343350493 is about 1103.3918700264.
The spelling of 1343350493 in words is "one billion, three hundred forty-three million, three hundred fifty thousand, four hundred ninety-three".
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