Base | Representation |
---|---|
bin | 11110100010110110100001… |
… | …011111011111110010000100 |
3 | 122121122102201210111002101020 |
4 | 132202312201133133302010 |
5 | 120101431422241133122 |
6 | 1153413142455431140 |
7 | 40203325155266211 |
oct | 3642664137376204 |
9 | 577572653432336 |
10 | 134336401505412 |
11 | 39892825563967 |
12 | 130973650854b0 |
13 | 59c5b3988ac22 |
14 | 2525cb8d30b08 |
15 | 107e5e8833c5c |
hex | 7a2da17dfc84 |
134336401505412 has 12 divisors (see below), whose sum is σ = 313451603512656. Its totient is φ = 44778800501800.
The previous prime is 134336401505399. The next prime is 134336401505447. The reversal of 134336401505412 is 214505104633431.
It is a tau number, because it is divible by the number of its divisors (12).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5597350062714 + ... + 5597350062737.
It is an arithmetic number, because the mean of its divisors is an integer number (26120966959388).
Almost surely, 2134336401505412 is an apocalyptic number.
134336401505412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
134336401505412 is an abundant number, since it is smaller than the sum of its proper divisors (179115202007244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134336401505412 is a wasteful number, since it uses less digits than its factorization.
134336401505412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11194700125458 (or 11194700125456 counting only the distinct ones).
The product of its (nonzero) digits is 518400, while the sum is 42.
The spelling of 134336401505412 in words is "one hundred thirty-four trillion, three hundred thirty-six billion, four hundred one million, five hundred five thousand, four hundred twelve".
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