Base | Representation |
---|---|
bin | 1100001101111101111110… |
… | …0101110010011111000111 |
3 | 1202120021210111111121122211 |
4 | 3003133133211302133013 |
5 | 3230101031133204004 |
6 | 44323314033204251 |
7 | 2554403603361364 |
oct | 303373745623707 |
9 | 52507714447584 |
10 | 13434113959879 |
11 | 430a415116068 |
12 | 160b755700687 |
13 | 765aa6aa0b22 |
14 | 346300b6d46b |
15 | 1846bae40504 |
hex | c37df9727c7 |
13434113959879 has 2 divisors, whose sum is σ = 13434113959880. Its totient is φ = 13434113959878.
The previous prime is 13434113959837. The next prime is 13434113959913. The reversal of 13434113959879 is 97895931143431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13434113959879 - 231 = 13431966476231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13434110959879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717056979939 + 6717056979940.
It is an arithmetic number, because the mean of its divisors is an integer number (6717056979940).
Almost surely, 213434113959879 is an apocalyptic number.
13434113959879 is a deficient number, since it is larger than the sum of its proper divisors (1).
13434113959879 is an equidigital number, since it uses as much as digits as its factorization.
13434113959879 is an evil number, because the sum of its binary digits is even.
The product of its digits is 88179840, while the sum is 67.
The spelling of 13434113959879 in words is "thirteen trillion, four hundred thirty-four billion, one hundred thirteen million, nine hundred fifty-nine thousand, eight hundred seventy-nine".
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