Base | Representation |
---|---|
bin | 11001000001011110… |
… | …01011011010110011 |
3 | 1021200020201001001022 |
4 | 30200233023122303 |
5 | 210003114442324 |
6 | 10101020130055 |
7 | 653624210624 |
oct | 144057133263 |
9 | 37606631038 |
10 | 13434140339 |
11 | 5774249524 |
12 | 272b09692b |
13 | 1361307989 |
14 | 916299a4b |
15 | 53960b05e |
hex | 320bcb6b3 |
13434140339 has 2 divisors, whose sum is σ = 13434140340. Its totient is φ = 13434140338.
The previous prime is 13434140303. The next prime is 13434140347. The reversal of 13434140339 is 93304143431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13434140339 - 216 = 13434074803 is a prime.
It is a super-3 number, since 3×134341403393 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 13434140299 and 13434140308.
It is not a weakly prime, because it can be changed into another prime (13434146339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717070169 + 6717070170.
It is an arithmetic number, because the mean of its divisors is an integer number (6717070170).
Almost surely, 213434140339 is an apocalyptic number.
13434140339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13434140339 is an equidigital number, since it uses as much as digits as its factorization.
13434140339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 35.
The spelling of 13434140339 in words is "thirteen billion, four hundred thirty-four million, one hundred forty thousand, three hundred thirty-nine".
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