Base | Representation |
---|---|
bin | 11001000001011110… |
… | …11010110100011111 |
3 | 1021200020211020120202 |
4 | 30200233122310133 |
5 | 210003124002143 |
6 | 10101021334115 |
7 | 653624562554 |
oct | 144057326437 |
9 | 37606736522 |
10 | 13434203423 |
11 | 5774291963 |
12 | 272b10733b |
13 | 136132a5c4 |
14 | 9162b4a2b |
15 | 53961eab8 |
hex | 320bdad1f |
13434203423 has 32 divisors (see below), whose sum is σ = 14747806080. Its totient is φ = 12201615360.
The previous prime is 13434203407. The next prime is 13434203449. The reversal of 13434203423 is 32430243431.
It is a cyclic number.
It is not a de Polignac number, because 13434203423 - 24 = 13434203407 is a prime.
It is a super-2 number, since 2×134342034232 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13434202423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7110863 + ... + 7112751.
It is an arithmetic number, because the mean of its divisors is an integer number (460868940).
Almost surely, 213434203423 is an apocalyptic number.
13434203423 is a deficient number, since it is larger than the sum of its proper divisors (1313602657).
13434203423 is a wasteful number, since it uses less digits than its factorization.
13434203423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2147.
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 13434203423 its reverse (32430243431), we get a palindrome (45864446854).
The spelling of 13434203423 in words is "thirteen billion, four hundred thirty-four million, two hundred three thousand, four hundred twenty-three".
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