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13434214104253 is a prime number
BaseRepresentation
bin1100001101111110010110…
…0011110011110010111101
31202120022001110221110220201
43003133211203303302331
53230101232302314003
644323332011443501
72554406230524445
oct303374543636275
952508043843821
1013434214104253
11430a4666a6008
12160b783156591
13765ac1765257
1434631019b125
151846c4b22b1d
hexc37e58f3cbd

13434214104253 has 2 divisors, whose sum is σ = 13434214104254. Its totient is φ = 13434214104252.

The previous prime is 13434214104191. The next prime is 13434214104317. The reversal of 13434214104253 is 35240141243431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9273377029284 + 4160837074969 = 3045222^2 + 2039813^2 .

It is a cyclic number.

It is not a de Polignac number, because 13434214104253 - 217 = 13434213973181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13434214104953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717107052126 + 6717107052127.

It is an arithmetic number, because the mean of its divisors is an integer number (6717107052127).

Almost surely, 213434214104253 is an apocalyptic number.

It is an amenable number.

13434214104253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13434214104253 is an equidigital number, since it uses as much as digits as its factorization.

13434214104253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 13434214104253 its reverse (35240141243431), we get a palindrome (48674355347684).

The spelling of 13434214104253 in words is "thirteen trillion, four hundred thirty-four billion, two hundred fourteen million, one hundred four thousand, two hundred fifty-three".