Base | Representation |
---|---|
bin | 1100001101111110010110… |
… | …0011110011110010111101 |
3 | 1202120022001110221110220201 |
4 | 3003133211203303302331 |
5 | 3230101232302314003 |
6 | 44323332011443501 |
7 | 2554406230524445 |
oct | 303374543636275 |
9 | 52508043843821 |
10 | 13434214104253 |
11 | 430a4666a6008 |
12 | 160b783156591 |
13 | 765ac1765257 |
14 | 34631019b125 |
15 | 1846c4b22b1d |
hex | c37e58f3cbd |
13434214104253 has 2 divisors, whose sum is σ = 13434214104254. Its totient is φ = 13434214104252.
The previous prime is 13434214104191. The next prime is 13434214104317. The reversal of 13434214104253 is 35240141243431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9273377029284 + 4160837074969 = 3045222^2 + 2039813^2 .
It is a cyclic number.
It is not a de Polignac number, because 13434214104253 - 217 = 13434213973181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13434214104953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717107052126 + 6717107052127.
It is an arithmetic number, because the mean of its divisors is an integer number (6717107052127).
Almost surely, 213434214104253 is an apocalyptic number.
It is an amenable number.
13434214104253 is a deficient number, since it is larger than the sum of its proper divisors (1).
13434214104253 is an equidigital number, since it uses as much as digits as its factorization.
13434214104253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 13434214104253 its reverse (35240141243431), we get a palindrome (48674355347684).
The spelling of 13434214104253 in words is "thirteen trillion, four hundred thirty-four billion, two hundred fourteen million, one hundred four thousand, two hundred fifty-three".
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