Base | Representation |
---|---|
bin | 11110100010111100000001… |
… | …101010101100110101111011 |
3 | 122121122222222120101212010022 |
4 | 132202330001222230311323 |
5 | 120102031022331210043 |
6 | 1153420001043441055 |
7 | 40203624451664501 |
oct | 3642740152546573 |
9 | 577588876355108 |
10 | 134342310022523 |
11 | 39895287790259 |
12 | 1309853398618b |
13 | 59c656ba05ab5 |
14 | 25262b9928671 |
15 | 107e8423ea868 |
hex | 7a2f01aacd7b |
134342310022523 has 2 divisors, whose sum is σ = 134342310022524. Its totient is φ = 134342310022522.
The previous prime is 134342310022457. The next prime is 134342310022559. The reversal of 134342310022523 is 325220013243431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134342310022523 is a prime.
It is not a weakly prime, because it can be changed into another prime (134342310022223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67171155011261 + 67171155011262.
It is an arithmetic number, because the mean of its divisors is an integer number (67171155011262).
Almost surely, 2134342310022523 is an apocalyptic number.
134342310022523 is a deficient number, since it is larger than the sum of its proper divisors (1).
134342310022523 is an equidigital number, since it uses as much as digits as its factorization.
134342310022523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 134342310022523 its reverse (325220013243431), we get a palindrome (459562323265954).
The spelling of 134342310022523 in words is "one hundred thirty-four trillion, three hundred forty-two billion, three hundred ten million, twenty-two thousand, five hundred twenty-three".
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