Base | Representation |
---|---|
bin | 11110100010111100010000… |
… | …010010000011111000101011 |
3 | 122121200000121122210020221122 |
4 | 132202330100102003320223 |
5 | 120102032023114042142 |
6 | 1153420041243125455 |
7 | 40203633520102451 |
oct | 3642742022037053 |
9 | 577600548706848 |
10 | 134342555221547 |
11 | 398953a3134982 |
12 | 130985a1b1388b |
13 | 59c65aa75718a |
14 | 25263003149d1 |
15 | 107e858bd21d2 |
hex | 7a2f10483e2b |
134342555221547 has 2 divisors, whose sum is σ = 134342555221548. Its totient is φ = 134342555221546.
The previous prime is 134342555221543. The next prime is 134342555221577. The reversal of 134342555221547 is 745122555243431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134342555221547 - 22 = 134342555221543 is a prime.
It is a super-2 number, since 2×1343425552215472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134342555221543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67171277610773 + 67171277610774.
It is an arithmetic number, because the mean of its divisors is an integer number (67171277610774).
Almost surely, 2134342555221547 is an apocalyptic number.
134342555221547 is a deficient number, since it is larger than the sum of its proper divisors (1).
134342555221547 is an equidigital number, since it uses as much as digits as its factorization.
134342555221547 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160000, while the sum is 53.
The spelling of 134342555221547 in words is "one hundred thirty-four trillion, three hundred forty-two billion, five hundred fifty-five million, two hundred twenty-one thousand, five hundred forty-seven".
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