Base | Representation |
---|---|
bin | 11110100010111100010000… |
… | …010010000011111000100111 |
3 | 122121200000121122210020221111 |
4 | 132202330100102003320213 |
5 | 120102032023114042133 |
6 | 1153420041243125451 |
7 | 40203633520102444 |
oct | 3642742022037047 |
9 | 577600548706844 |
10 | 134342555221543 |
11 | 398953a3134979 |
12 | 130985a1b13887 |
13 | 59c65aa757186 |
14 | 25263003149cb |
15 | 107e858bd21cd |
hex | 7a2f10483e27 |
134342555221543 has 2 divisors, whose sum is σ = 134342555221544. Its totient is φ = 134342555221542.
The previous prime is 134342555221529. The next prime is 134342555221547. The reversal of 134342555221543 is 345122555243431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134342555221543 - 245 = 99158183132711 is a prime.
It is a super-2 number, since 2×1343425552215432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134342555221547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67171277610771 + 67171277610772.
It is an arithmetic number, because the mean of its divisors is an integer number (67171277610772).
Almost surely, 2134342555221543 is an apocalyptic number.
134342555221543 is a deficient number, since it is larger than the sum of its proper divisors (1).
134342555221543 is an equidigital number, since it uses as much as digits as its factorization.
134342555221543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8640000, while the sum is 49.
The spelling of 134342555221543 in words is "one hundred thirty-four trillion, three hundred forty-two billion, five hundred fifty-five million, two hundred twenty-one thousand, five hundred forty-three".
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