1343442251453 has 4 divisors (see below), whose sum is σ = 1343465906940. Its totient is φ = 1343418595968.

The previous prime is 1343442251381. The next prime is 1343442251507. The reversal of 1343442251453 is 3541522443431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 149813895364 + 1193628356089 = 387058^2 + 1092533^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1343442251453 is a prime.

It is a super-2 number, since 2×1343442251453² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1343442251453.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343442251153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11742350 + ... + 11856207.

It is an arithmetic number, because the mean of its divisors is an integer number (335866476735).

Almost surely, 2^{1343442251453} is an apocalyptic number.

It is an amenable number.

1343442251453 is a deficient number, since it is larger than the sum of its proper divisors (23655487).

1343442251453 is an equidigital number, since it uses as much as digits as its factorization.

1343442251453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23655486.

The product of its digits is 691200, while the sum is 41.

Adding to 1343442251453 its reverse (3541522443431), we get a palindrome (4884964694884).

The spelling of 1343442251453 in words is "one trillion, three hundred forty-three billion, four hundred forty-two million, two hundred fifty-one thousand, four hundred fifty-three".