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13434435121 is a prime number
BaseRepresentation
bin11001000001100000…
…10011011000110001
31021200021021000102011
430200300103120301
5210003203410441
610101030322521
7653626546222
oct144060233061
937607230364
1013434435121
11577442aa48
12272b1b9441
1313613abbc3
14916335249
15539668581
hex320c13631

13434435121 has 2 divisors, whose sum is σ = 13434435122. Its totient is φ = 13434435120.

The previous prime is 13434435067. The next prime is 13434435137. The reversal of 13434435121 is 12153443431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12927690000 + 506745121 = 113700^2 + 22511^2 .

It is an emirp because it is prime and its reverse (12153443431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13434435121 - 29 = 13434434609 is a prime.

It is not a weakly prime, because it can be changed into another prime (13434435151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717217560 + 6717217561.

It is an arithmetic number, because the mean of its divisors is an integer number (6717217561).

Almost surely, 213434435121 is an apocalyptic number.

It is an amenable number.

13434435121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13434435121 is an equidigital number, since it uses as much as digits as its factorization.

13434435121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17280, while the sum is 31.

Adding to 13434435121 its reverse (12153443431), we get a palindrome (25587878552).

The spelling of 13434435121 in words is "thirteen billion, four hundred thirty-four million, four hundred thirty-five thousand, one hundred twenty-one".