Base | Representation |
---|---|
bin | 10011100011001011111… |
… | …001000111000010011011 |
3 | 11202102200101012200211012 |
4 | 103203023321013002123 |
5 | 134002341314322420 |
6 | 2505101143324135 |
7 | 166026646123154 |
oct | 23431371070233 |
9 | 4672611180735 |
10 | 1343450542235 |
11 | 47883289772a |
12 | 198452a5064b |
13 | 998c0cba969 |
14 | 4904811c92b |
15 | 24e2d7e9dc5 |
hex | 138cbe4709b |
1343450542235 has 4 divisors (see below), whose sum is σ = 1612140650688. Its totient is φ = 1074760433784.
The previous prime is 1343450542219. The next prime is 1343450542261. The reversal of 1343450542235 is 5322450543431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1343450542235 - 24 = 1343450542219 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1343450542192 and 1343450542201.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134345054219 + ... + 134345054228.
It is an arithmetic number, because the mean of its divisors is an integer number (403035162672).
Almost surely, 21343450542235 is an apocalyptic number.
1343450542235 is a deficient number, since it is larger than the sum of its proper divisors (268690108453).
1343450542235 is an equidigital number, since it uses as much as digits as its factorization.
1343450542235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 268690108452.
The product of its (nonzero) digits is 864000, while the sum is 41.
The spelling of 1343450542235 in words is "one trillion, three hundred forty-three billion, four hundred fifty million, five hundred forty-two thousand, two hundred thirty-five".
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