Base | Representation |
---|---|
bin | 10011100011001111100… |
… | …000100111101110101111 |
3 | 11202102211121102000201022 |
4 | 103203033200213232233 |
5 | 134003002333401112 |
6 | 2505111152204355 |
7 | 166031314020422 |
oct | 23431740475657 |
9 | 4672747360638 |
10 | 1343511231407 |
11 | 478864079374 |
12 | 19846b2396bb |
13 | 99900749507 |
14 | 490521d99b9 |
15 | 24e33cd6d72 |
hex | 138cf827baf |
1343511231407 has 2 divisors, whose sum is σ = 1343511231408. Its totient is φ = 1343511231406.
The previous prime is 1343511231373. The next prime is 1343511231443. The reversal of 1343511231407 is 7041321153431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1343511231407 - 26 = 1343511231343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343511231457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671755615703 + 671755615704.
It is an arithmetic number, because the mean of its divisors is an integer number (671755615704).
Almost surely, 21343511231407 is an apocalyptic number.
1343511231407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343511231407 is an equidigital number, since it uses as much as digits as its factorization.
1343511231407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 35.
Adding to 1343511231407 its reverse (7041321153431), we get a palindrome (8384832384838).
The spelling of 1343511231407 in words is "one trillion, three hundred forty-three billion, five hundred eleven million, two hundred thirty-one thousand, four hundred seven".
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