134354301404411 has 4 divisors (see below), whose sum is σ = 146568328804824. Its totient is φ = 122140274004000.

The previous prime is 134354301404383. The next prime is 134354301404473. The reversal of 134354301404411 is 114404103453431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134354301404411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134354301400411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6107013700190 + ... + 6107013700211.

It is an arithmetic number, because the mean of its divisors is an integer number (36642082201206).

Almost surely, 2^{134354301404411} is an apocalyptic number.

134354301404411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

134354301404411 is a deficient number, since it is larger than the sum of its proper divisors (12214027400413).

134354301404411 is a wasteful number, since it uses less digits than its factorization.

134354301404411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12214027400412.

The product of its (nonzero) digits is 138240, while the sum is 38.

Adding to 134354301404411 its reverse (114404103453431), we get a palindrome (248758404857842).

The spelling of 134354301404411 in words is "one hundred thirty-four trillion, three hundred fifty-four billion, three hundred one million, four hundred four thousand, four hundred eleven".