Base | Representation |
---|---|
bin | 11110100011001111011001… |
… | …101110000110010011101111 |
3 | 122121201222200110222222222221 |
4 | 132203033121232012103233 |
5 | 120102401124323123403 |
6 | 1153433321315220211 |
7 | 40205262144334456 |
oct | 3643173156062357 |
9 | 577658613888887 |
10 | 134363114661103 |
11 | 398a3093429139 |
12 | 130a057b2a7667 |
13 | 59c8505cc8a23 |
14 | 25272d0a25b9d |
15 | 108015db07dbd |
hex | 7a33d9b864ef |
134363114661103 has 4 divisors (see below), whose sum is σ = 134386857927880. Its totient is φ = 134339371394328.
The previous prime is 134363114661029. The next prime is 134363114661143. The reversal of 134363114661103 is 301166411363431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134363114661103 - 217 = 134363114530031 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 134363114661103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134363114661143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11871624900 + ... + 11871636217.
It is an arithmetic number, because the mean of its divisors is an integer number (33596714481970).
Almost surely, 2134363114661103 is an apocalyptic number.
134363114661103 is a deficient number, since it is larger than the sum of its proper divisors (23743266777).
134363114661103 is an equidigital number, since it uses as much as digits as its factorization.
134363114661103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23743266776.
The product of its (nonzero) digits is 279936, while the sum is 43.
The spelling of 134363114661103 in words is "one hundred thirty-four trillion, three hundred sixty-three billion, one hundred fourteen million, six hundred sixty-one thousand, one hundred three".
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