Base | Representation |
---|---|
bin | 11001000001110000… |
… | …10100101011010101 |
3 | 1021200102012211102011 |
4 | 30200320110223111 |
5 | 210004223200212 |
6 | 10101143344221 |
7 | 653653453612 |
oct | 144070245325 |
9 | 37612184364 |
10 | 13436537557 |
11 | 57756365a3 |
12 | 272ba52071 |
13 | 1361966b51 |
14 | 916721509 |
15 | 5399314a7 |
hex | 320e14ad5 |
13436537557 has 2 divisors, whose sum is σ = 13436537558. Its totient is φ = 13436537556.
The previous prime is 13436537467. The next prime is 13436537599. The reversal of 13436537557 is 75573563431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11433169476 + 2003368081 = 106926^2 + 44759^2 .
It is an emirp because it is prime and its reverse (75573563431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13436537557 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13436537557.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13436534557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6718268778 + 6718268779.
It is an arithmetic number, because the mean of its divisors is an integer number (6718268779).
Almost surely, 213436537557 is an apocalyptic number.
It is an amenable number.
13436537557 is a deficient number, since it is larger than the sum of its proper divisors (1).
13436537557 is an equidigital number, since it uses as much as digits as its factorization.
13436537557 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3969000, while the sum is 49.
The spelling of 13436537557 in words is "thirteen billion, four hundred thirty-six million, five hundred thirty-seven thousand, five hundred fifty-seven".
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