134365462304053 has 4 divisors (see below), whose sum is σ = 134366744656620. Its totient is φ = 134364179951488.

The previous prime is 134365462304011. The next prime is 134365462304093. The reversal of 134365462304053 is 350403264563431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 16006576675684 + 118358885628369 = 4000822^2 + 10879287^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134365462304053 is a prime.

It is a super-3 number, since 3×134365462304053³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134365462303988 and 134365462304006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134365462304093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641019100 + ... + 641228677.

It is an arithmetic number, because the mean of its divisors is an integer number (33591686164155).

Almost surely, 2^{134365462304053} is an apocalyptic number.

It is an amenable number.

134365462304053 is a deficient number, since it is larger than the sum of its proper divisors (1282352567).

134365462304053 is a wasteful number, since it uses less digits than its factorization.

134365462304053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1282352566.

The product of its (nonzero) digits is 9331200, while the sum is 49.

The spelling of 134365462304053 in words is "one hundred thirty-four trillion, three hundred sixty-five billion, four hundred sixty-two million, three hundred four thousand, fifty-three".