Base | Representation |
---|---|
bin | 1100001110001101101010… |
… | …1010001110001100000111 |
3 | 1202120200200001120202010121 |
4 | 3003203122222032030013 |
5 | 3230133143002000033 |
6 | 44325252024202411 |
7 | 2554613152014112 |
oct | 303433252161407 |
9 | 52520601522117 |
10 | 13438326203143 |
11 | 4311186894846 |
12 | 1610530309407 |
13 | 7662c867546a |
14 | 3465c0371579 |
15 | 184865b3c62d |
hex | c38daa8e307 |
13438326203143 has 2 divisors, whose sum is σ = 13438326203144. Its totient is φ = 13438326203142.
The previous prime is 13438326203069. The next prime is 13438326203149. The reversal of 13438326203143 is 34130262383431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13438326203143 is a prime.
It is a super-2 number, since 2×134383262031432 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13438326203143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13438326203149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6719163101571 + 6719163101572.
It is an arithmetic number, because the mean of its divisors is an integer number (6719163101572).
Almost surely, 213438326203143 is an apocalyptic number.
13438326203143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13438326203143 is an equidigital number, since it uses as much as digits as its factorization.
13438326203143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 746496, while the sum is 43.
Adding to 13438326203143 its reverse (34130262383431), we get a palindrome (47568588586574).
The spelling of 13438326203143 in words is "thirteen trillion, four hundred thirty-eight billion, three hundred twenty-six million, two hundred three thousand, one hundred forty-three".
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