13438326203147 has 4 divisors (see below), whose sum is σ = 13468661025720. Its totient is φ = 13407991380576.

The previous prime is 13438326203143. The next prime is 13438326203149. The reversal of 13438326203147 is 74130262383431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13438326203147 - 2² = 13438326203143 is a prime.

It is a super-2 number, since 2×13438326203147² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13438326203143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15167410622 + ... + 15167411507.

It is an arithmetic number, because the mean of its divisors is an integer number (3367165256430).

Almost surely, 2^{13438326203147} is an apocalyptic number.

13438326203147 is a deficient number, since it is larger than the sum of its proper divisors (30334822573).

13438326203147 is an equidigital number, since it uses as much as digits as its factorization.

13438326203147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30334822572.

The product of its (nonzero) digits is 1741824, while the sum is 47.

Adding to 13438326203147 its reverse (74130262383431), we get a palindrome (87568588586578).

The spelling of 13438326203147 in words is "thirteen trillion, four hundred thirty-eight billion, three hundred twenty-six million, two hundred three thousand, one hundred forty-seven".