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134400000011 = 294634482759
BaseRepresentation
bin111110100101011011…
…1010100000000001011
3110211220120022101221012
41331022313110000023
54200222400000021
6141424214234135
712465362102504
oct1751267240013
9424816271835
10134400000011
1151aa9329282
122206a35594b
13c89b637834
14670d9c3bab
15376929c35b
hex1f4add400b

134400000011 has 4 divisors (see below), whose sum is σ = 139034482800. Its totient is φ = 129765517224.

The previous prime is 134399999989. The next prime is 134400000023. The reversal of 134400000011 is 110000004431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110000004431 = 503921829729.

It is a cyclic number.

It is not a de Polignac number, because 134400000011 - 210 = 134399998987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134400000061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2317241351 + ... + 2317241408.

It is an arithmetic number, because the mean of its divisors is an integer number (34758620700).

Almost surely, 2134400000011 is an apocalyptic number.

134400000011 is a deficient number, since it is larger than the sum of its proper divisors (4634482789).

134400000011 is an equidigital number, since it uses as much as digits as its factorization.

134400000011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4634482788.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 134400000011 its reverse (110000004431), we get a palindrome (244400004442).

The spelling of 134400000011 in words is "one hundred thirty-four billion, four hundred million, eleven", and thus it is an aban number.

Divisors: 1 29 4634482759 134400000011